Math: Factoring expressions that already have brackets
The tutor shows a technique for factoring expressions that contain brackets. The technique may be called compound factoring.
Example: factor (2x-1)2 – 5(2x-1) – 24
Solution:
- Substitue A for (2x-1), then rewrite:
A2 – 5A – 24 -
The expression is now an easy trinomial (see my post here) and factors like so:
(A – 8)(A + 3) -
Now resubstitute (2x-1) for A:
((2x-1) -8)((2x-1) + 3) -
Simplifying, we get
(2x-9)(2x+2)
The substitution method is very useful for this type of question:)
Source:
Travers, Kenneth et al. Using Advanced Algebra. Toronto: Doubleday Canada, 1977.
Jack of Oracle Tutoring by Jack and Diane, Campbell River, BC.
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