Math: Factoring expressions that already have brackets

The tutor shows a technique for factoring expressions that contain brackets. The technique may be called compound factoring.

Example: factor (2x-1)2 – 5(2x-1) – 24

Solution:

  1. Substitue A for (2x-1), then rewrite:
    A2 – 5A – 24
  2. The expression is now an easy trinomial (see my post here) and factors like so:
    (A – 8)(A + 3)
  3. Now resubstitute (2x-1) for A:
    ((2x-1) -8)((2x-1) + 3)
  4. Simplifying, we get
    (2x-9)(2x+2)

The substitution method is very useful for this type of question:)

Source:

Travers, Kenneth et al. Using Advanced Algebra. Toronto: Doubleday Canada, 1977.

Jack of Oracle Tutoring by Jack and Diane, Campbell River, BC.

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