{"id":12730,"date":"2015-10-19T16:46:10","date_gmt":"2015-10-19T16:46:10","guid":{"rendered":"http:\/\/www.oracletutoring.ca\/blog\/?p=12730"},"modified":"2017-09-09T18:15:36","modified_gmt":"2017-09-09T18:15:36","slug":"physics-projectile-motion-time-in-air-over-level-ground","status":"publish","type":"post","link":"https:\/\/www.oracletutoring.ca\/blog\/physics-projectile-motion-time-in-air-over-level-ground\/","title":{"rendered":"Physics:  projectile motion:  time in air over level ground"},"content":{"rendered":"<h1>The tutor continues about projectile motion.<\/h1>\n<p>Back in my <a href=\"?p=12690\">Oct 16 post<\/a>, I began exploration of a projectile&#8217;s motion. The context is a golf ball shot at 55m\/s, 27\u00b0 elevation, over level ground. The post from October 16 resolves the velocity as follows:<\/p>\n<p>v<sub>x<\/sub>=49m\/s<br \/>\nv<sub>y<\/sub>=25m\/s<\/p>\n<p>Consider the next question:<\/p>\n<p><strong>Find the golf ball&#8217;s time in the air.<\/strong><\/p>\n<p>Solution:<\/p>\n<p>v<sub>y<\/sub> is the focus here. When the golf ball reaches the top of its flight, v<sub>y<\/sub>=0.0m\/s. Moreover, that&#8217;s at exactly half the flight time.<\/p>\n<p>We find the time it takes for v<sub>y<\/sub> to reach 0.0m\/s:<\/p>\n<p>\u0394v=at<\/p>\n<p>which implies<\/p>\n<p>t=\u0394v\/a = 0.0-25\/-9.8 = -25\/-9.8=2.6s<\/p>\n<p>The &#8220;up&#8221; trip takes 2.6s; returning to the ground takes the same. The golf ball&#8217;s time in the air is 2.6&#215;2=5.2s.<\/p>\n<p>I&#8217;ll be continuing about projectile motion:)<\/p>\n<p>Source:<\/p>\n<p>Giancoli, Douglas C. <u>Physics<\/u>. New Jersey: Prentice Hall, 1998.<\/p>\n<p>Jack of <a href=\"https:\/\/www.oracletutoring.ca\">Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The tutor continues about projectile motion. Back in my Oct 16 post, I began exploration of a projectile&#8217;s motion. The context is a golf ball shot at 55m\/s, 27\u00b0 elevation, over level ground. The post from October 16 resolves the &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/www.oracletutoring.ca\/blog\/physics-projectile-motion-time-in-air-over-level-ground\/\"> <span class=\"screen-reader-text\">Physics:  projectile motion:  time in air over level ground<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[7],"tags":[1133,1123,1134,1135],"class_list":["post-12730","post","type-post","status-publish","format-standard","hentry","category-physics","tag-flight-time-of-a-projectile","tag-projectile-motion","tag-projectile-time-in-air","tag-projectile-with-oblique-trajectory"],"_links":{"self":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/12730","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/comments?post=12730"}],"version-history":[{"count":17,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/12730\/revisions"}],"predecessor-version":[{"id":23539,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/12730\/revisions\/23539"}],"wp:attachment":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/media?parent=12730"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/categories?post=12730"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/tags?post=12730"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}