{"id":12756,"date":"2015-10-21T16:40:41","date_gmt":"2015-10-21T16:40:41","guid":{"rendered":"http:\/\/www.oracletutoring.ca\/blog\/?p=12756"},"modified":"2017-09-09T18:08:05","modified_gmt":"2017-09-09T18:08:05","slug":"physics-projectile-motion-maximum-height","status":"publish","type":"post","link":"https:\/\/www.oracletutoring.ca\/blog\/physics-projectile-motion-maximum-height\/","title":{"rendered":"Physics:  projectile motion:  maximum height"},"content":{"rendered":"<h1>Continuing about projectiles, the tutor finds the maximum height of the golf ball.<\/h1>\n<p>My post from <a href=\"?p=12690\">Oct 16<\/a> sets the premise:  a golf ball is struck at 55m\/s at 27\u00b0 elevation.  The velocity is resolved thus:<\/p>\n<p>v<sub>x<\/sub>=49m\/s<\/p>\n<p>v<sub>y<\/sub>=25m\/s<\/p>\n<p>To find the maximum height, we focus on v<sub>y<\/sub>.  Specifically, when  v<sub>y<\/sub>=0, the ball is at max height.<\/p>\n<p>We can use the formula<\/p>\n<p>v<sub>f<\/sub>^2=v<sub>i<\/sub>^2+2ad<\/p>\n<p>in which v<sub>f<\/sub> is the final velocity; v<sub>i<\/sub> , the initial; a, the acceleration due to gravity; d, the displacement (in this case, the vertical displacement: the height).<\/p>\n<p>0^2=25^2+2(-9.8)d<\/p>\n<p>0=625 -19.6d<\/p>\n<p>19.6d=625<\/p>\n<p>d=625\/19.6=32m<\/p>\n<p>The golf ball reaches max height of 32m.<\/p>\n<p>HTH:)<\/p>\n<p>Source:<\/p>\n<p>Giancoli, Douglas C.  <u>Physics<\/u>.  New Jersey:  Prentice Hall, 1998.<\/p>\n<p>Jack of <a href=\"https:\/\/www.oracletutoring.ca\">Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Continuing about projectiles, the tutor finds the maximum height of the golf ball. My post from Oct 16 sets the premise: a golf ball is struck at 55m\/s at 27\u00b0 elevation. The velocity is resolved thus: vx=49m\/s vy=25m\/s To find &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/www.oracletutoring.ca\/blog\/physics-projectile-motion-maximum-height\/\"> <span class=\"screen-reader-text\">Physics:  projectile motion:  maximum height<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[901,7],"tags":[1137,1123],"class_list":["post-12756","post","type-post","status-publish","format-standard","hentry","category-kinematics","category-physics","tag-maximum-height-of-a-projectile","tag-projectile-motion"],"_links":{"self":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/12756","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/comments?post=12756"}],"version-history":[{"count":13,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/12756\/revisions"}],"predecessor-version":[{"id":23536,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/12756\/revisions\/23536"}],"wp:attachment":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/media?parent=12756"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/categories?post=12756"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/tags?post=12756"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}