{"id":19994,"date":"2017-02-07T16:42:12","date_gmt":"2017-02-07T16:42:12","guid":{"rendered":"http:\/\/www.oracletutoring.ca\/blog\/?p=19994"},"modified":"2017-02-07T16:42:12","modified_gmt":"2017-02-07T16:42:12","slug":"chemistry-equivalent-weight-acid-or-base","status":"publish","type":"post","link":"https:\/\/www.oracletutoring.ca\/blog\/chemistry-equivalent-weight-acid-or-base\/","title":{"rendered":"Chemistry:  equivalent weight:  acid or base"},"content":{"rendered":"<h1>The tutor defines equivalent weight in the context of acids and bases.<\/h1>\n<p>An <em>equivalent weight<\/em> of an acid is the mass that yields one mole of H<sup>+<\/sup> ions.  Similarly, an equivalent weight of a base is the mass that yields one mole of OH<sup>&#8211;<\/sup> ions.<\/p>\n<p><strong>Example:<\/strong><\/p>\n<p>Find the mass of three equivalent weights of H<sub>2<\/sub>SO<sub>4<\/sub>.<\/p>\n<p>Solution:  The molar mass of H<sub>2<\/sub>SO<sub>4<\/sub> is 98g, but that yields two moles of H<sup>+<\/sup> ions.  Therefore, an equivalent weight of H<sub>2<\/sub>SO<sub>4<\/sub> is 49g.  Three equivalent weights is 3*49g = 147g.<\/p>\n<p>By way of comparison, the molar mass of HCl is 36.5g, and one mole supplies one mole H<sup>+<\/sup> ions.  Therefore, three equivalent weights of HCl is 3&#215;36.5g = 109.5g.<\/p>\n<p>Source:<\/p>\n<p>Mortimer, Charles E.  <u>Chemistry<\/u>, 6th ed.  Belmont:  Wadsworth, 1986.<\/p>\n<p>Jack of <a href=\"https:\/\/www.oracletutoring.ca\">Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The tutor defines equivalent weight in the context of acids and bases. An equivalent weight of an acid is the mass that yields one mole of H+ ions. Similarly, an equivalent weight of a base is the mass that yields &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/www.oracletutoring.ca\/blog\/chemistry-equivalent-weight-acid-or-base\/\"> <span class=\"screen-reader-text\">Chemistry:  equivalent weight:  acid or base<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-19994","post","type-post","status-publish","format-standard","hentry","category-chemistry"],"_links":{"self":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/19994","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/comments?post=19994"}],"version-history":[{"count":15,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/19994\/revisions"}],"predecessor-version":[{"id":20009,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/19994\/revisions\/20009"}],"wp:attachment":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/media?parent=19994"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/categories?post=19994"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/tags?post=19994"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}