{"id":20149,"date":"2017-02-18T20:31:36","date_gmt":"2017-02-18T20:31:36","guid":{"rendered":"http:\/\/www.oracletutoring.ca\/blog\/?p=20149"},"modified":"2017-02-18T20:31:36","modified_gmt":"2017-02-18T20:31:36","slug":"chemistry-a-textbook-correction","status":"publish","type":"post","link":"https:\/\/www.oracletutoring.ca\/blog\/chemistry-a-textbook-correction\/","title":{"rendered":"Chemistry:  a textbook correction"},"content":{"rendered":"<h1>The tutor suggests a correction to example 11.2 in <u>Chemistry<\/u> (sixth edition) by Charles E. Mortimer.<\/u><\/h1>\n<p>Example 11.2 (page 275) of said textbook is about the Clausius-Clapeyron equation.  At one point, the equation becomes<\/p>\n<p style=\"text-align:center\">log(0.526\/p<sub>1<\/sub>) = 0.491<\/p>\n<p>Then, the antilog is taken; the next line <em>should<\/em> read<\/p>\n<p style=\"text-align:center\">0.526\/p<sub>1<\/sub> = <strong>3.10<\/strong><\/p>\n<p>From there, what follows agrees with the text:<\/p>\n<p style=\"text-align:center\">p<sub>1<\/sub> = 0.170<\/p>\n<p>HTH:)<\/p>\n<p>Source:<\/p>\n<p>Mortimer, Charles E.  <u>Chemistry<\/u>, sixth edition.  Belmont:  Wadsworth, 1986.<\/p>\n<p>Jack of <a href=\"https:\/\/www.oracletutoring.ca\">Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The tutor suggests a correction to example 11.2 in Chemistry (sixth edition) by Charles E. Mortimer. Example 11.2 (page 275) of said textbook is about the Clausius-Clapeyron equation. At one point, the equation becomes log(0.526\/p1) = 0.491 Then, the antilog &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/www.oracletutoring.ca\/blog\/chemistry-a-textbook-correction\/\"> <span class=\"screen-reader-text\">Chemistry:  a textbook correction<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[2141],"class_list":["post-20149","post","type-post","status-publish","format-standard","hentry","category-chemistry","tag-mortimer-chemistry-6th-ed"],"_links":{"self":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/20149","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/comments?post=20149"}],"version-history":[{"count":19,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/20149\/revisions"}],"predecessor-version":[{"id":20168,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/20149\/revisions\/20168"}],"wp:attachment":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/media?parent=20149"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/categories?post=20149"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/tags?post=20149"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}