\nToday something came across the desk: estimate the charge on a capacitor, 1\u00b5F, assumed to have been of zero charge, after receiving current through 100k\u03a9 for around a tenth of a second: source voltage: 9V.<\/p>\n
\nThe last time I faced such a problem wasn’t yesterday; I had to look up the formula, which I guess is<\/p>\n
Vcap<\/sub> = Vin<\/sub>(1-e-t\/(R*C)<\/sup>)<\/blockquote>\n\nTherefore, in such a case, the voltage across the capacitor after charging for 1\/10 of a second might be about<\/p>\n
\nVcap<\/sub> = 9(1-e-0.1\/(10^5*10^-6)<\/sup>) \u2248 5.7V<\/p>\n
\nInteresting, eh?<\/p>\n
Source:<\/p>\n
phys.libretexts.org<\/a><\/p>\n
\ncompart.com<\/a><\/p>\nJack of Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.\n","protected":false},"excerpt":{"rendered":"
Self-tutoring about how quickly a capacitor gains voltage: the tutor does a calculation. Today something came across the desk: estimate the charge on a capacitor, 1\u00b5F, assumed to have been of zero charge, after receiving current through 100k\u03a9 for around …<\/p>\n