\nQuestion: Suppose Gear A (14 teeth) and Gear B (21 teeth) are enmeshed. If Gear B turns 60 rpm, how fast does Gear A turn?<\/p>\n
\nSolution: the idea is that the same number of teeth are contacted, for each gear, during a given time. At 60 rpm, in one minute, 60*21=1260 total teeth are contacted for Gear B. Therefore, 1260 teeth must also be contacted for Gear A during that same minute. Gear A’s number of turns for that minute will be 1260\/14 = 90 turns. So, Gear A turns at 90 rpm, if Gear B turns at 60 rpm.<\/p>\n
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\nTravers, K.J., Dalton, L.C., Brunner, B.F. and Taylor, A.R. (1977). Using Advanced Algebra.<\/em> Doubleday Canada Limited.<\/p>\nJack of Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.\n\n","protected":false},"excerpt":{"rendered":" Tutoring math, problems might come up about the turns (rpm) of one gear relative to another. The tutor mentions an example. Question: Suppose Gear A (14 teeth) and Gear B (21 teeth) are enmeshed. If Gear B turns 60 rpm, …<\/p>\n