{"id":8875,"date":"2015-03-04T21:18:10","date_gmt":"2015-03-04T21:18:10","guid":{"rendered":"http:\/\/www.oracletutoring.ca\/blog\/?p=8875"},"modified":"2017-09-07T18:05:32","modified_gmt":"2017-09-07T18:05:32","slug":"chemistry-molar-volume-of-an-ideal-gas","status":"publish","type":"post","link":"https:\/\/www.oracletutoring.ca\/blog\/chemistry-molar-volume-of-an-ideal-gas\/","title":{"rendered":"Chemistry:  molar volume of an ideal gas"},"content":{"rendered":"<h1>One of the fundamental topics in chemistry is calculating between volume and moles of a gas.<\/h1>\n<p>In chemistry, you hear people mention &#8220;at STP&#8221;.\u00a0 STP means <strong>standard temperature and pressure<\/strong>.\u00a0 Standard pressure is 1 atmosphere; standard temperature, curiously, is 0\u00b0C.<\/p>\n<p>The relevance of standard temperature and pressure is that, at those particular settings, the volume of an ideal gas is 22.4L\/mole.\u00a0 Note that the molar volume is independent of the molar mass of the gas, so long as it closely follows the &#8220;ideal gas&#8221; concept.\u00a0 Mortimer reports that, at STP, most gases closely follow ideal behaviour.<\/p>\n<p><strong>Example:\u00a0 Find the volume of 1.000 kg of CO<sub>2<\/sub> at STP.<\/strong><\/p>\n<p>Solution: We must first convert the mass to moles (see my post <a href=\"?p=6076\">here<\/a> and perhaps even <a href=\"?p=6756\">here<\/a> for more about that), as follows (M.M. meaning molar mass):<\/p>\n<p>From the periodic table of the elements, M.M. of CO<sub>2<\/sub>=12.0g+2(16.0g)=44.0g<\/p>\n<p>We proceed with our conversion from kilograms to L, using the factor 22.4L\/mol:<\/p>\n<p>1) 1.000kg=1000.g<\/p>\n<p>2) 1000.g x 1mol CO<sub>2<\/sub>\/44.0g = 22.7273mol CO<sub>2<\/sub><\/p>\n<p>3) 22.7273mol CO<sub>2<\/sub> x 22.4L\/mol = 509L CO<sub>2<\/sub><\/p>\n<p>The one-line chemistry method you might see on the board combines the steps:<\/p>\n<p>1.000kg x 1000.g\/kg x 1mol CO<sub>2<\/sub>\/44.0g x 22.4L\/mol = 509L CO<sub>2<\/sub><\/p>\n<p>Apparently, based on the molar volume of 22.4L\/mol, 1.000kg of CO<sub>2<\/sub> has volume 509L at STP (1 atmosphere and 0\u00b0C).<\/p>\n<p>There is much more to say about volumes of gases. I&#8217;ll be talking more about them in future posts.<\/p>\n<p>HTH:)<\/p>\n<p>Source:<\/p>\n<p>Mortimer, Charles E. <em>Chemistry<\/em>, 6th Ed. Belmont: Wadsworth, 1986.<\/p>\n<p>Jack of <a href=\"https:\/\/www.oracletutoring.ca\">Oracle Tutoring by Jack and Diane,<\/a> Campbell River, BC.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>One of the fundamental topics in chemistry is calculating between volume and moles of a gas. In chemistry, you hear people mention &#8220;at STP&#8221;.\u00a0 STP means standard temperature and pressure.\u00a0 Standard pressure is 1 atmosphere; standard temperature, curiously, is 0\u00b0C. &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/www.oracletutoring.ca\/blog\/chemistry-molar-volume-of-an-ideal-gas\/\"> <span class=\"screen-reader-text\">Chemistry:  molar volume of an ideal gas<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[566,567,564,565],"class_list":["post-8875","post","type-post","status-publish","format-standard","hentry","category-chemistry","tag-22-4-litres-per-mole","tag-ideal-gas","tag-molar-volume","tag-stp"],"_links":{"self":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/8875","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/comments?post=8875"}],"version-history":[{"count":21,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/8875\/revisions"}],"predecessor-version":[{"id":23444,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/posts\/8875\/revisions\/23444"}],"wp:attachment":[{"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/media?parent=8875"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/categories?post=8875"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.oracletutoring.ca\/blog\/wp-json\/wp\/v2\/tags?post=8875"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}