In yesterday’s post<\/a> I brought up regular expressions with an interactive example. Today, some more depth:<\/p>\n Let’s imagine an input string that means an amount of money. Likely, the amount includes a currency symbol; perhaps it’s<\/p>\n $1 117.89<\/span><\/p>\n or<\/p>\n \u20ac1 117.89<\/span><\/p>\n To Javascript, the presence of a currency symbol means the string is not a number. The same goes for the space between the digits. Therefore, if calculation is to be done on the number, it must be amended to Let’s imagine the input is contained in the string catch0<\/span>, like so: The replace()<\/span> function must be applied to a string. It can use the following syntax: For instance, let’s imagine the string Further, let’s imagine that we want to replace at<\/span> with @<\/span>. We could do so as follows: Now, the value of numailstring<\/span> is mail@somewhere.there<\/span><\/p>\n This doesn’t quite explain the workings of the example from last post, but it’s on the way. I’ll be continuing …:)<\/p>\n Source:<\/p>\n w3schools.com<\/a><\/p>\n
\n
\n1117.89
\n<\/span><\/p>\n
\n
\nvar catch0=”\u20ac1 117.89″;
\n<\/span>
\nEverything but the digits and decimal point needs to be removed. The replace()<\/span> function can be used, as follows:
\n
\nvar catch1=catch0.replace(\/[^0-9.]\/g,””);
\n<\/span><\/p>\n
\n
\nthestring.replace(\/to_be_replaced\/,”replacement”);<\/p>\n
\n
\nvar mailstring=”mailatsomewhere.there”;
\n<\/span><\/p>\n
\n
\nvar numailstring=mailstring.replace(\/at\/, “@”);
\n<\/span><\/p>\n