Math: number theory: a formula for generating Pythagorean triples
The tutor continues his discussion about Pythagorean triples.
Back in my January 7, 2016 post I brought up Pythagorean triples, which are all-integer solutions to
x² + y² = z²
The equation above is based on the familiar
a² + b² = c²
An interesting fact is that Pythagorean triples can be generated from the following formulas, with n odd:
| x | n |
| y | (n²-1)/2 |
| z | (n²+1)/2 |


Take, for instance, n as 3. Then we have
x=3
y=(3²-1)/2=(9-1)/2=8/2=4 3(2)/2 + 2/2=4
z=(3²+1)/2=(9+1)/2=10/2=5
which is the familiar 3,4,5 triple.
With n=11, we have
x=11
y=(11²-1)/2=(120)/2=60
z=(11²+1)/2=(122)/2=61
Checking, we start with
11²+60²=61²
Squaring, we get
121+3600=3721✓
I’ll be giving more coverage to Pythagorean triples in coming posts:)
Source:
Dudley, Underwood. Elementary Number Theory. New York:
W H Freeman and Company, 1978.
Jack of Oracle Tutoring by Jack and Diane, Campbell River, BC.
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