Electronics: capacitor voltage

Self-tutoring about how quickly a capacitor gains voltage: the tutor does a calculation.

Today something came across the desk: estimate the charge on a capacitor, 1µF, assumed to have been of zero charge, after receiving current through 100kΩ for around a tenth of a second: source voltage: 9V.

The last time I faced such a problem wasn’t yesterday; I had to look up the formula, which I guess is

V_cap = V_in(1-e^-t/(R*C))

Therefore, in such a case, the voltage across the capacitor after charging for 1/10 of a second might be about

V_cap = 9(1-e^{-0.1/(10^5*10^-6)}) ≈ 5.7V

Interesting, eh?

Source:

phys.libretexts.org

compart.com