Math: Finding Square Root or Cube Root from Prime Factorization
The math tutor continues to appreciate prime factorization for all it yields.
Let’s imagine you need to determine the square root of a number without a calculator. This challenge is part of the curriculum for local high school students.
Example: Determine if each number can be square rooted (to a whole number). If so, find its square root.
a) 540
b) 576
Before tackling the above problem, let’s dissect a number we know to be a perfect square.
Example: Confirm, by prime factorization, that the square root of 900 is 30.
Solution: We recall that a prime number is one that cannot be divided into smaller numbers, then break 900 down into primes:
900=10×90=(2×5)(9×10)=(2×5)(3x3x2x5)=2x5x3x3x2x5
Rearranging, we get
900=2x2x3x3x5x5=(2x3x5)(2x3x5)
We notice 900 can be broken into two identical groupings like so:
900 = (2x3x5)(2x3x5)
Therefore, the square root of 900 is 2x3x5=30
We now know what to seek: if a number is square rootable, its prime factorization can be organized into two equal groups. The square root is simply the product of one of the groups.
Back to our example:
Determine the whole number square root (if it exists) of the following:
a) 540
b) 576
Solution:
a) First we break 540 into primes:
540=10×54=(2×5)(6×9)=(2×5)(2x3x3x3)=2x2x3x3x3x5
With only one 5 in the prime factorization, we can’t separate it into two equal groups. 540 doesn’t have a whole number square root.
b) 2 and 4 both go into 576. Without a calculator, you either do it mentally or else use long division. To get started, just break it in half:
576=2×288=2(2×144)=2(2x12x12)=2(2x(3×4)(3×4))=2x2x3x4x3x4
Since we have only multiplication here, we can add and rearrange brackets at will. However, with mixed operations we wouldn’t be able to do so:)
Rearranging, we get
576=2x2x3x3x4x4=(2x3x4)(2x3x4)
Clearly, the prime factorization of 576 is separable into two equal groupings of 2x3x4. 2x3x4 = 24, so the square root of 576 is 24.
If its prime factorization can be separated into three equal groupings, the number is a perfect cube:
Example: Confirm that 9261 is a perfect cube.
Solution: We’ll break this one down using short division. Since 9+2+6+1=18, we know 9 divides into it:

Since 1+0+2+9=12, we know 3 divides into it (because 3 divides into 12).

Since 3+4+3=10 (which 3 doesn’t divide into), and 343 doesn’t end in 5 or 0, the next number to try is 7:

So we see that we can break down 9261 as follows:
9261=9(1029)=9(3×343)=9(3x7x49)=(3×3)(3x7x7x7)=3x3x3x7x7x7
Rearranging, we separate the prime factorization into three equal groupings:
9261=3x3x3x7x7x7=(3×7)(3×7)(3×7)
Therefore, 9261 is a perfect cube with cube root=3×7=21. The cube root of 9261 is 21.
Once again, short division was used to break down 9261. For more explanation about that very handy technique, please check future posts:)
Jack of Oracle Tutoring by Jack and Diane, Campbell River, BC.
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