Math: non-permissible values: when there aren’t any (over the Reals)
The tutor does a follow-up about non-permissible values.
Back in my April 23 post I wrote about non-permissible values. You may want to visit there for a briefing.
Today, I’ll point out a situation where there aren’t any non-permissible values: in the following situation, x can be any real number:
1/(bx2+a), both a, b > 0
The reason:
bx2 + a = 0 has no solutions when both a, b > 0
Jack of Oracle Tutoring by Jack and Diane, Campbell River, BC.