Math: non-permissible values: when there aren’t any (over the Reals)

The tutor does a follow-up about non-permissible values.

Back in my April 23 post I wrote about non-permissible values. You may want to visit there for a briefing.

Today, I’ll point out a situation where there aren’t any non-permissible values: in the following situation, x can be any real number:

1/(bx2+a), both a, b > 0

The reason:

bx2 + a = 0 has no solutions when both a, b > 0

Jack of Oracle Tutoring by Jack and Diane, Campbell River, BC.

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