Tutoring calculus, everyday formulas students count on can often be verified. The tutor mentions the derivative of tanx. It’s true that (tanx)’ = (secx)^2. But why? Realizing tanx = sinx/cosx, then using the the quotient rule (u/v)’ = (vu’ – …

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The tutor shows how to remind yourself that the derivative of tanx is sec2x. Let’s imagine you don’t recall that (tanx)’=sec2x. Here’s how to reconstruct it: Recall that tanx=sinx/cosx Take the derivative of sinx/cosx using the quotient rule:(u/v)’ = (vu’-uv’)/v2 …

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