## Physics: projectile motion: maximum height

Continuing about projectiles, the tutor finds the maximum height of the golf ball. My post from Oct 16 sets the premise: a golf ball is struck at 55m/s at 27° elevation. The velocity is resolved thus: vx=49m/s vy=25m/s To find …

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## Physics: projectile motion: range of a projectile

Continuing with the golfing premise, the tutor finds the range of the projectile. While this post continues from yesterday’s, its premise begins with my Oct 16 one. We have a projectile whose horizontal velocity is 49m/s (see Oct 16), whose …

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## Physics: projectile motion: time in air over level ground

The tutor continues about projectile motion. Back in my Oct 16 post, I began exploration of a projectile’s motion. The context is a golf ball shot at 55m/s, 27° elevation, over level ground. The post from October 16 resolves the …

## Physics: projectile motion: finding the horizontal and vertical components of velocity

The tutor gets started with projectiles. Consider the following question: A golf ball is hit over level ground at 55m/s with angle of elevation 27°. Find the vertical and horizontal components of its velocity. Solution: We draw a diagram of …